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最近业务升级,之前的身份证校验正则只能保证身份证位数满足条件,但是格式不进行校验.
写一个可以校验格式的身份证校验

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// 校验函数
function IdentityCodeValid(rule, value, callback) {
let city = {
11: '北京',
12: '天津',
13: '河北',
14: '山西',
15: '内蒙古',
21: '辽宁',
22: '吉林',
23: '黑龙江',
31: '上海',
32: '江苏',
33: '浙江',
34: '安徽',
35: '福建',
36: '江西',
37: '山东',
41: '河南',
42: '湖北',
43: '湖南',
44: '广东',
45: '广西',
46: '海南',
50: '重庆',
51: '四川',
52: '贵州',
53: '云南',
54: '西藏',
61: '陕西',
62: '甘肃',
63: '青海',
64: '宁夏',
65: '新疆',
71: '台湾',
81: '香港',
82: '澳门',
91: '国外',
};
if(!value){
return true, callback();
}
if (
!value ||
!/^\d{6}(18|19|20)?\d{2}(0[1-9]|1[012])(0[1-9]|[12]\d|3[01])\d{3}(\d|X)$/i.test(
value
)
) {
callback(new Error('身份证号格式错误'));
} else if (!city[value.substr(0, 2)]) {
callback(new Error('地址编码错误'));
} else {
if (value.length == 18) {
value = value.split('');
let factor = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2];
let parity = [1, 0, 'X', 9, 8, 7, 6, 5, 4, 3, 2];
let sum = 0;
let ai = 0;
let wi = 0;
for (let i = 0; i < 17; i++) {
ai = value[i];
wi = factor[i];
sum += ai * wi;
}
if (parity[sum % 11] != value[17]) {
callback(new Error('校验位错误'));
} else {
return true, callback();
}
}
}
}

el-form加rules属性

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<el-form :rules="rules" >

el-form-item 加prop

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<el-form-item label="身份证号" prop="legalIdNumber">
<el-input v-model="Defendantenterprise.IdNumber" :disabled="disable"></el-input>
</el-form-item>

data中rules属性

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rules:{
idNumber: [
{
validator: IdentityCodeValid,
trigger: 'blur',
},
],
}